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 Post subject: a math question
PostPosted: Wed May 30, 2012 2:15 am 
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Joined: Thu Apr 05, 2012 2:14 pm
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I've got this math problem in my head which I just can't seem to figure out. It seems pretty simple, but something's just not ringing in me.

Question:
"Find, in a bi form, the two roots of the equation 1-x3 = x3"

I've already found one root...

1-x3 = x3
1-x = x
1 = 2x
x = 1/2

But how would I go about getting the other root?


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 Post subject: Re: a math question
PostPosted: Wed May 30, 2012 10:57 pm 
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Joined: Thu Jul 05, 2012 11:55 am
Posts: 64
If the equation is 1 – 3x = 3x , then the only solution is x = 1/6 .
If the equation is 1 – x³ = x³ , then the only solution is x = ³√(1/2) .

In either case there is only one solution and 1/2 is not it.


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