We know that angle AEO is equal to 90° since the angle created by a radius and a tangent line is always 90°. We also know that angle ACO is 45° because CDOF is a square and CO is its diagonal (CDOF is a square because all of its angles are 90° and DO = OF as radii).
Now we can solve for angle EOD: Angle EOD = 360° – 60° – 45° – 90° = 165°.
The correct answer is D. ---------- Why wouldn't angle ADO be 90 degrees (line DO is the radius and it hits a tangential line of the triangle)?
If it were 90 degrees then the answer would be 360 – 60 – 90 – 90 = 120 degrees
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